1/2(4r^2-2r)=6

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Solution for 1/2(4r^2-2r)=6 equation: 


r in (-oo:+oo)

(1/2)*(4*r^2-(2*r)) = 6 // - 6

(1/2)*(4*r^2-(2*r))-6 = 0

(1/2)*(4*r^2-2*r)-6 = 0

1/2*(4*r^2-2*r)-6 = 0

1/2*(4*r^2-2*r)-6 = 0

2*r^2-r-6 = 0

2*r^2-r-6 = 0

2*r^2-r-6 = 0

DELTA = (-1)^2-(-6*2*4)

DELTA = 49

DELTA > 0

r = (49^(1/2)+1)/(2*2) or r = (1-49^(1/2))/(2*2)

r = 2 or r = -3/2

(r+3/2)*(r-2) = 0

(r+3/2)*(r-2) = 0

( r+3/2 )

r+3/2 = 0 // - 3/2

r = -3/2

( r-2 )

r-2 = 0 // + 2

r = 2

r in { -3/2, 2 }

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